4011111012133 has 2 divisors, whose sum is σ = 4011111012134. Its totient is φ = 4011111012132.

The previous prime is 4011111012109. The next prime is 4011111012169. The reversal of 4011111012133 is 3312101111104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2885099279364 + 1126011732769 = 1698558^2 + 1061137^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4011111012133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4011111012133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4011111012193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005555506066 + 2005555506067.

It is an arithmetic number, because the mean of its divisors is an integer number (2005555506067).

Almost surely, 2^{4011111012133} is an apocalyptic number.

It is an amenable number.

4011111012133 is a deficient number, since it is larger than the sum of its proper divisors (1).

4011111012133 is an equidigital number, since it uses as much as digits as its factorization.

4011111012133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 4011111012133 its reverse (3312101111104), we get a palindrome (7323212123237).

The spelling of 4011111012133 in words is "four trillion, eleven billion, one hundred eleven million, twelve thousand, one hundred thirty-three".