Base | Representation |
---|---|
bin | 111010010111111010010… |
… | …000111100000010011111 |
3 | 112012111010120212212122112 |
4 | 322113322100330002133 |
5 | 1011210323211401031 |
6 | 12310451352504235 |
7 | 562546211606513 |
oct | 72277220740237 |
9 | 15174116785575 |
10 | 4011403231391 |
11 | 1307254602146 |
12 | 54952a9ab07b |
13 | 23137342642a |
14 | dc21d9b6143 |
15 | 6e52c14a62b |
hex | 3a5fa43c09f |
4011403231391 has 2 divisors, whose sum is σ = 4011403231392. Its totient is φ = 4011403231390.
The previous prime is 4011403231379. The next prime is 4011403231393. The reversal of 4011403231391 is 1931323041104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4011403231391 - 26 = 4011403231327 is a prime.
Together with 4011403231393, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4011403231393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005701615695 + 2005701615696.
It is an arithmetic number, because the mean of its divisors is an integer number (2005701615696).
Almost surely, 24011403231391 is an apocalyptic number.
4011403231391 is a deficient number, since it is larger than the sum of its proper divisors (1).
4011403231391 is an equidigital number, since it uses as much as digits as its factorization.
4011403231391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 32.
Adding to 4011403231391 its reverse (1931323041104), we get a palindrome (5942726272495).
The spelling of 4011403231391 in words is "four trillion, eleven billion, four hundred three million, two hundred thirty-one thousand, three hundred ninety-one".
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