Base | Representation |
---|---|
bin | 1111010011100001000111 |
3 | 21112211120102 |
4 | 33103201013 |
5 | 2011341403 |
6 | 221554315 |
7 | 46050044 |
oct | 17234107 |
9 | 7484512 |
10 | 4012103 |
11 | 22a0397 |
12 | 141599b |
13 | aa6234 |
14 | 7661cb |
15 | 543b88 |
hex | 3d3847 |
4012103 has 2 divisors, whose sum is σ = 4012104. Its totient is φ = 4012102.
The previous prime is 4012081. The next prime is 4012109. The reversal of 4012103 is 3012104.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4012103 - 218 = 3749959 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4012109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006051 + 2006052.
It is an arithmetic number, because the mean of its divisors is an integer number (2006052).
Almost surely, 24012103 is an apocalyptic number.
4012103 is a deficient number, since it is larger than the sum of its proper divisors (1).
4012103 is an equidigital number, since it uses as much as digits as its factorization.
4012103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 11.
The square root of 4012103 is about 2003.0234646654. The cubic root of 4012103 is about 158.9000466153.
Adding to 4012103 its reverse (3012104), we get a palindrome (7024207).
Subtracting from 4012103 its reverse (3012104), we obtain a palindrome (999999).
The spelling of 4012103 in words is "four million, twelve thousand, one hundred three".
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