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40131322143 = 3111216100671
BaseRepresentation
bin100101011000000000…
…110110000100011111
310211120211011101121120
4211120000312010133
51124142104302033
630234105302023
72620330416123
oct453000660437
9124524141546
1040131322143
11160240a3340
12793ba94913
133a27341a83
141d29bd3583
15109d2c71b3
hex95803611f

40131322143 has 8 divisors (see below), whose sum is σ = 58372832256. Its totient is φ = 24322013400.

The previous prime is 40131322141. The next prime is 40131322157. The reversal of 40131322143 is 34122313104.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 40131322143 - 21 = 40131322141 is a prime.

It is a super-2 number, since 2×401313221432 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40131322141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 608050303 + ... + 608050368.

It is an arithmetic number, because the mean of its divisors is an integer number (7296604032).

Almost surely, 240131322143 is an apocalyptic number.

40131322143 is a deficient number, since it is larger than the sum of its proper divisors (18241510113).

40131322143 is a wasteful number, since it uses less digits than its factorization.

40131322143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1216100685.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 40131322143 its reverse (34122313104), we get a palindrome (74253635247).

The spelling of 40131322143 in words is "forty billion, one hundred thirty-one million, three hundred twenty-two thousand, one hundred forty-three".

Divisors: 1 3 11 33 1216100671 3648302013 13377107381 40131322143