Search a number
-
+
4021331213 is a prime number
BaseRepresentation
bin1110111110110000…
…1010010100001101
3101101020211210101002
43233230022110031
531213430044323
61503011030045
7201436515464
oct35754122415
911336753332
104021331213
111783a33729
1294289b325
134c117ca33
142a21079db
1518808a828
hexefb0a50d

4021331213 has 2 divisors, whose sum is σ = 4021331214. Its totient is φ = 4021331212.

The previous prime is 4021331207. The next prime is 4021331219. The reversal of 4021331213 is 3121331204.

It is a balanced prime because it is at equal distance from previous prime (4021331207) and next prime (4021331219).

It can be written as a sum of positive squares in only one way, i.e., 3747031369 + 274299844 = 61213^2 + 16562^2 .

It is a cyclic number.

It is not a de Polignac number, because 4021331213 - 224 = 4004553997 is a prime.

It is a super-2 number, since 2×40213312132 = 32342209449296102738, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4021331219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010665606 + 2010665607.

It is an arithmetic number, because the mean of its divisors is an integer number (2010665607).

Almost surely, 24021331213 is an apocalyptic number.

It is an amenable number.

4021331213 is a deficient number, since it is larger than the sum of its proper divisors (1).

4021331213 is an equidigital number, since it uses as much as digits as its factorization.

4021331213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 4021331213 is about 63413.9670183155. The cubic root of 4021331213 is about 1590.2178166319.

Adding to 4021331213 its reverse (3121331204), we get a palindrome (7142662417).

Subtracting from 4021331213 its reverse (3121331204), we obtain a palindrome (900000009).

The spelling of 4021331213 in words is "four billion, twenty-one million, three hundred thirty-one thousand, two hundred thirteen".