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402241130231 is a prime number
BaseRepresentation
bin1011101101001110111…
…00001000111011110111
31102110020212122120201012
411312213130020323313
523042242212131411
6504441555222435
741026624123253
oct5664734107367
91373225576635
10402241130231
111456536a4746
1265b598a7a1b
132bc14a40ac5
141567baa9263
15a6e353c18b
hex5da7708ef7

402241130231 has 2 divisors, whose sum is σ = 402241130232. Its totient is φ = 402241130230.

The previous prime is 402241130197. The next prime is 402241130233. The reversal of 402241130231 is 132031142204.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 402241130231 - 218 = 402240868087 is a prime.

It is a super-2 number, since 2×4022411302312 (a number of 24 digits) contains 22 as substring.

Together with 402241130233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 402241130197 and 402241130206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (402241130233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201120565115 + 201120565116.

It is an arithmetic number, because the mean of its divisors is an integer number (201120565116).

Almost surely, 2402241130231 is an apocalyptic number.

402241130231 is a deficient number, since it is larger than the sum of its proper divisors (1).

402241130231 is an equidigital number, since it uses as much as digits as its factorization.

402241130231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 402241130231 its reverse (132031142204), we get a palindrome (534272272435).

The spelling of 402241130231 in words is "four hundred two billion, two hundred forty-one million, one hundred thirty thousand, two hundred thirty-one".