Base | Representation |
---|---|
bin | 100101011110000110… |
… | …010100010101100011 |
3 | 10211211221021111201112 |
4 | 211132012110111203 |
5 | 1124344223421011 |
6 | 30252153453535 |
7 | 2623010266652 |
oct | 453606242543 |
9 | 124757244645 |
10 | 40233420131 |
11 | 16076798043 |
12 | 796a1112ab |
13 | 3a4253b498 |
14 | 1d395ad199 |
15 | 10a724358b |
hex | 95e194563 |
40233420131 has 2 divisors, whose sum is σ = 40233420132. Its totient is φ = 40233420130.
The previous prime is 40233420067. The next prime is 40233420133. The reversal of 40233420131 is 13102433204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40233420131 - 26 = 40233420067 is a prime.
It is a super-2 number, since 2×402334201312 (a number of 22 digits) contains 22 as substring.
Together with 40233420133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 40233420097 and 40233420106.
It is not a weakly prime, because it can be changed into another prime (40233420133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20116710065 + 20116710066.
It is an arithmetic number, because the mean of its divisors is an integer number (20116710066).
Almost surely, 240233420131 is an apocalyptic number.
40233420131 is a deficient number, since it is larger than the sum of its proper divisors (1).
40233420131 is an equidigital number, since it uses as much as digits as its factorization.
40233420131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 40233420131 its reverse (13102433204), we get a palindrome (53335853335).
The spelling of 40233420131 in words is "forty billion, two hundred thirty-three million, four hundred twenty thousand, one hundred thirty-one".
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