Base | Representation |
---|---|
bin | 100101100000010010… |
… | …111000100000110111 |
3 | 10211221111121121010212 |
4 | 211200102320200313 |
5 | 1124433142042341 |
6 | 30255551340035 |
7 | 2623635430346 |
oct | 454022704067 |
9 | 124844547125 |
10 | 40270268471 |
11 | 16095575814 |
12 | 797a52161b |
13 | 3a4a070634 |
14 | 1d40441b5d |
15 | 10aa5c15eb |
hex | 9604b8837 |
40270268471 has 2 divisors, whose sum is σ = 40270268472. Its totient is φ = 40270268470.
The previous prime is 40270268417. The next prime is 40270268473. The reversal of 40270268471 is 17486207204.
It is a happy number.
Together with previous prime (40270268417) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40270268471 - 218 = 40270006327 is a prime.
It is a super-3 number, since 3×402702684713 (a number of 33 digits) contains 333 as substring.
Together with 40270268473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40270268473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20135134235 + 20135134236.
It is an arithmetic number, because the mean of its divisors is an integer number (20135134236).
Almost surely, 240270268471 is an apocalyptic number.
40270268471 is a deficient number, since it is larger than the sum of its proper divisors (1).
40270268471 is an equidigital number, since it uses as much as digits as its factorization.
40270268471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 150528, while the sum is 41.
The spelling of 40270268471 in words is "forty billion, two hundred seventy million, two hundred sixty-eight thousand, four hundred seventy-one".
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