4051112143301 has 2 divisors, whose sum is σ = 4051112143302. Its totient is φ = 4051112143300.

The previous prime is 4051112143279. The next prime is 4051112143303. The reversal of 4051112143301 is 1033412111504.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2150326027201 + 1900786116100 = 1466399^2 + 1378690^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4051112143301 is a prime.

Together with 4051112143303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4051112143303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2025556071650 + 2025556071651.

It is an arithmetic number, because the mean of its divisors is an integer number (2025556071651).

Almost surely, 2^{4051112143301} is an apocalyptic number.

It is an amenable number.

4051112143301 is a deficient number, since it is larger than the sum of its proper divisors (1).

4051112143301 is an equidigital number, since it uses as much as digits as its factorization.

4051112143301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 4051112143301 its reverse (1033412111504), we get a palindrome (5084524254805).

The spelling of 4051112143301 in words is "four trillion, fifty-one billion, one hundred twelve million, one hundred forty-three thousand, three hundred one".