Base | Representation |
---|---|
bin | 100110001011111010… |
… | …101011100001010100 |
3 | 10220211111201120111012 |
4 | 212023322223201110 |
5 | 1132433020340200 |
6 | 30500333431352 |
7 | 2651033165150 |
oct | 461372534124 |
9 | 126744646435 |
10 | 41002121300 |
11 | 164306a0668 |
12 | 7b4363b558 |
13 | 3b3588314a |
14 | 1dad70c060 |
15 | 10ee986a35 |
hex | 98beab854 |
41002121300 has 36 divisors (see below), whose sum is σ = 101685262560. Its totient is φ = 14057869920.
The previous prime is 41002121291. The next prime is 41002121333. The reversal of 41002121300 is 312120014.
41002121300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (14).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 29286530 + ... + 29287929.
Almost surely, 241002121300 is an apocalyptic number.
It is an amenable number.
41002121300 is an abundant number, since it is smaller than the sum of its proper divisors (60683141260).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41002121300 is a wasteful number, since it uses less digits than its factorization.
41002121300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58574480 (or 58574473 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 41002121300 its reverse (312120014), we get a palindrome (41314241314).
The spelling of 41002121300 in words is "forty-one billion, two million, one hundred twenty-one thousand, three hundred".
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