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4100214103 is a prime number
BaseRepresentation
bin1111010001100100…
…0100110101010111
3101120202021110100121
43310121010311113
531344123322403
61514505452411
7203415146656
oct36431046527
911522243317
104100214103
1118145115a7
129651a1107
1350460b7bb
142ac79d19d
1518ee6d3bd
hexf4644d57

4100214103 has 2 divisors, whose sum is σ = 4100214104. Its totient is φ = 4100214102.

The previous prime is 4100214091. The next prime is 4100214119. The reversal of 4100214103 is 3014120014.

It is an a-pointer prime, because the next prime (4100214119) can be obtained adding 4100214103 to its sum of digits (16).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4100214103 is a prime.

It is a super-3 number, since 3×41002141033 (a number of 30 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4100214133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2050107051 + 2050107052.

It is an arithmetic number, because the mean of its divisors is an integer number (2050107052).

Almost surely, 24100214103 is an apocalyptic number.

4100214103 is a deficient number, since it is larger than the sum of its proper divisors (1).

4100214103 is an equidigital number, since it uses as much as digits as its factorization.

4100214103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 4100214103 is about 64032.9142160499. The cubic root of 4100214103 is about 1600.5485232580.

Adding to 4100214103 its reverse (3014120014), we get a palindrome (7114334117).

The spelling of 4100214103 in words is "four billion, one hundred million, two hundred fourteen thousand, one hundred three".