Search a number
-
+
41101132013 is a prime number
BaseRepresentation
bin100110010001110100…
…011000000011101101
310221002102000211122122
4212101310120003231
51133133342211023
630514231522325
72653344600134
oct462164300355
9127072024578
1041101132013
11164815768a7
127b708293a5
133b5023b576
141dbc92291b
1511084e32c8
hex991d180ed

41101132013 has 2 divisors, whose sum is σ = 41101132014. Its totient is φ = 41101132012.

The previous prime is 41101131991. The next prime is 41101132103. The reversal of 41101132013 is 31023110114.

Together with next prime (41101132103) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37672092649 + 3429039364 = 194093^2 + 58558^2 .

It is a cyclic number.

It is not a de Polignac number, because 41101132013 - 216 = 41101066477 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41101131982 and 41101132000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41101132313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20550566006 + 20550566007.

It is an arithmetic number, because the mean of its divisors is an integer number (20550566007).

Almost surely, 241101132013 is an apocalyptic number.

It is an amenable number.

41101132013 is a deficient number, since it is larger than the sum of its proper divisors (1).

41101132013 is an equidigital number, since it uses as much as digits as its factorization.

41101132013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 41101132013 its reverse (31023110114), we get a palindrome (72124242127).

The spelling of 41101132013 in words is "forty-one billion, one hundred one million, one hundred thirty-two thousand, thirteen".