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41102114132 = 2210275528533
BaseRepresentation
bin100110010001111000…
…000111110101010100
310221002110212201212102
4212101320013311110
51133134120123012
630514304541232
72653356130352
oct462170076524
9127073781772
1041102114132
1116482087772
127b71021818
133b504c35c1
141dbcada7d2
1511086392c2
hex991e07d54

41102114132 has 6 divisors (see below), whose sum is σ = 71928699738. Its totient is φ = 20551057064.

The previous prime is 41102114101. The next prime is 41102114159. The reversal of 41102114132 is 23141120114.

It can be written as a sum of positive squares in only one way, i.e., 35229037636 + 5873076496 = 187694^2 + 76636^2 .

It is a super-2 number, since 2×411021141322 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5137764263 + ... + 5137764270.

It is an arithmetic number, because the mean of its divisors is an integer number (11988116623).

Almost surely, 241102114132 is an apocalyptic number.

It is an amenable number.

41102114132 is a deficient number, since it is larger than the sum of its proper divisors (30826585606).

41102114132 is a wasteful number, since it uses less digits than its factorization.

41102114132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10275528537 (or 10275528535 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 41102114132 its reverse (23141120114), we get a palindrome (64243234246).

The spelling of 41102114132 in words is "forty-one billion, one hundred two million, one hundred fourteen thousand, one hundred thirty-two".

Divisors: 1 2 4 10275528533 20551057066 41102114132