41102114133 has 4 divisors (see below), whose sum is σ = 54802818848. Its totient is φ = 27401409420.

The previous prime is 41102114101. The next prime is 41102114159. The reversal of 41102114133 is 33141120114.

41102114133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 41102114133 - 2⁵ = 41102114101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41102112133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6850352353 + ... + 6850352358.

It is an arithmetic number, because the mean of its divisors is an integer number (13700704712).

Almost surely, 2^41102114133 is an apocalyptic number.

It is an amenable number.

41102114133 is a deficient number, since it is larger than the sum of its proper divisors (13700704715).

41102114133 is a wasteful number, since it uses less digits than its factorization.

41102114133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13700704714.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 41102114133 its reverse (33141120114), we get a palindrome (74243234247).

The spelling of 41102114133 in words is "forty-one billion, one hundred two million, one hundred fourteen thousand, one hundred thirty-three".