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411023110055 = 582204622011
BaseRepresentation
bin1011111101100101110…
…00101110111110100111
31110021220220111101021012
411332302320232332213
523213233404010210
6512453231412435
741460351535055
oct5766270567647
91407826441235
10411023110055
1114934a915108
12677aa98411b
132c9b429787c
1415c7216b1d5
15aa59500305
hex5fb2e2efa7

411023110055 has 4 divisors (see below), whose sum is σ = 493227732072. Its totient is φ = 328818488040.

The previous prime is 411023110027. The next prime is 411023110061. The reversal of 411023110055 is 550011320114.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 550011320114 = 2275005660057.

It is not a de Polignac number, because 411023110055 - 212 = 411023105959 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 411023110055.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41102311001 + ... + 41102311010.

It is an arithmetic number, because the mean of its divisors is an integer number (123306933018).

Almost surely, 2411023110055 is an apocalyptic number.

411023110055 is a deficient number, since it is larger than the sum of its proper divisors (82204622017).

411023110055 is an equidigital number, since it uses as much as digits as its factorization.

411023110055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82204622016.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 411023110055 its reverse (550011320114), we get a palindrome (961034430169).

The spelling of 411023110055 in words is "four hundred eleven billion, twenty-three million, one hundred ten thousand, fifty-five".

Divisors: 1 5 82204622011 411023110055