Base | Representation |
---|---|
bin | 10010101100100001100010… |
… | …10000101011100001000000 |
3 | 12101120021220121221200021122 |
4 | 21112100301100223201000 |
5 | 20342040343333212230 |
6 | 223234413011011412 |
7 | 11442155652054506 |
oct | 1126206120534100 |
9 | 171507817850248 |
10 | 41112253413440 |
11 | 12110677291a30 |
12 | 473b9b6599b68 |
13 | 19c2b3ab73821 |
14 | a21bb50c8676 |
15 | 4b46562e8be5 |
hex | 25643142b840 |
41112253413440 has 56 divisors (see below), whose sum is σ = 106798421944512. Its totient is φ = 14949910330880.
The previous prime is 41112253413353. The next prime is 41112253413487. The reversal of 41112253413440 is 4431435221114.
It is a self number, because there is not a number n which added to its sum of digits gives 41112253413440.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5839805204 + ... + 5839812243.
Almost surely, 241112253413440 is an apocalyptic number.
41112253413440 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
41112253413440 is an abundant number, since it is smaller than the sum of its proper divisors (65686168531072).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41112253413440 is a wasteful number, since it uses less digits than its factorization.
41112253413440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11679617475 (or 11679617465 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 41112253413440 its reverse (4431435221114), we get a palindrome (45543688634554).
The spelling of 41112253413440 in words is "forty-one trillion, one hundred twelve billion, two hundred fifty-three million, four hundred thirteen thousand, four hundred forty".
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