Base | Representation |
---|---|
bin | 100110010010100111… |
… | …001010000101100010 |
3 | 10221010100002011110000 |
4 | 212102213022011202 |
5 | 1133200244203010 |
6 | 30515425120430 |
7 | 2653566003024 |
oct | 462247120542 |
9 | 127110064400 |
10 | 41114444130 |
11 | 16489039451 |
12 | 7b75189116 |
13 | 3b52c1c866 |
14 | 1dc05ca014 |
15 | 11097727c0 |
hex | 9929ca162 |
41114444130 has 40 divisors (see below), whose sum is σ = 110552174172. Its totient is φ = 10963851552.
The previous prime is 41114444123. The next prime is 41114444131. The reversal of 41114444130 is 3144441114.
It can be written as a sum of positive squares in 2 ways, for example, as 40966164801 + 148279329 = 202401^2 + 12177^2 .
It is a super-2 number, since 2×411144441302 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 41114444094 and 41114444103.
It is not an unprimeable number, because it can be changed into a prime (41114444131) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 25378477 + ... + 25380096.
Almost surely, 241114444130 is an apocalyptic number.
41114444130 is an abundant number, since it is smaller than the sum of its proper divisors (69437730042).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41114444130 is a wasteful number, since it uses less digits than its factorization.
41114444130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50758592 (or 50758583 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 41114444130 its reverse (3144441114), we get a palindrome (44258885244).
The spelling of 41114444130 in words is "forty-one billion, one hundred fourteen million, four hundred forty-four thousand, one hundred thirty".
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