4112113330351 has 4 divisors (see below), whose sum is σ = 4428429740392. Its totient is φ = 3795796920312.

The previous prime is 4112113330301. The next prime is 4112113330363. The reversal of 4112113330351 is 1530333112114.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4112113330351 - 2¹⁷ = 4112113199279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4112113330301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 158158205001 + ... + 158158205026.

It is an arithmetic number, because the mean of its divisors is an integer number (1107107435098).

Almost surely, 2^{4112113330351} is an apocalyptic number.

4112113330351 is a deficient number, since it is larger than the sum of its proper divisors (316316410041).

4112113330351 is a wasteful number, since it uses less digits than its factorization.

4112113330351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 316316410040.

The product of its (nonzero) digits is 3240, while the sum is 28.

Adding to 4112113330351 its reverse (1530333112114), we get a palindrome (5642446442465).

The spelling of 4112113330351 in words is "four trillion, one hundred twelve billion, one hundred thirteen million, three hundred thirty thousand, three hundred fifty-one".