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4112301005 = 51953816743
BaseRepresentation
bin1111010100011100…
…1011101111001101
3101121121000112110122
43311013023233031
531410222113010
61520020514325
7203622660521
oct36507135715
911547015418
104112301005
11182031767a
1296924b9a5
13506c81207
142b0227d81
15191059855
hexf51cbbcd

4112301005 has 16 divisors (see below), whose sum is σ = 5292501120. Its totient is φ = 3057882048.

The previous prime is 4112300999. The next prime is 4112301013. The reversal of 4112301005 is 5001032114.

It is a cyclic number.

It is not a de Polignac number, because 4112301005 - 214 = 4112284621 is a prime.

It is a super-2 number, since 2×41123010052 = 33822039111448020050, which contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 403337 + ... + 413406.

It is an arithmetic number, because the mean of its divisors is an integer number (330781320).

Almost surely, 24112301005 is an apocalyptic number.

It is an amenable number.

4112301005 is a deficient number, since it is larger than the sum of its proper divisors (1180200115).

4112301005 is a wasteful number, since it uses less digits than its factorization.

4112301005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 816820.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 4112301005 is about 64127.2251465787. The cubic root of 4112301005 is about 1602.1197172019.

Adding to 4112301005 its reverse (5001032114), we get a palindrome (9113333119).

The spelling of 4112301005 in words is "four billion, one hundred twelve million, three hundred one thousand, five".

Divisors: 1 5 19 53 95 265 1007 5035 816743 4083715 15518117 43287379 77590585 216436895 822460201 4112301005