411230110013 has 4 divisors (see below), whose sum is σ = 412569622080. Its totient is φ = 409890597948.

The previous prime is 411230109971. The next prime is 411230110021. The reversal of 411230110013 is 310011032114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 411230110013 - 2¹² = 411230105917 is a prime.

It is a super-2 number, since 2×411230110013² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 411230109973 and 411230110000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411230110043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 669755573 + ... + 669756186.

It is an arithmetic number, because the mean of its divisors is an integer number (103142405520).

Almost surely, 2^411230110013 is an apocalyptic number.

It is an amenable number.

411230110013 is a deficient number, since it is larger than the sum of its proper divisors (1339512067).

411230110013 is a wasteful number, since it uses less digits than its factorization.

411230110013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1339512066.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 411230110013 its reverse (310011032114), we get a palindrome (721241142127).

The spelling of 411230110013 in words is "four hundred eleven billion, two hundred thirty million, one hundred ten thousand, thirteen".