4113000312 has 16 divisors (see below), whose sum is σ = 10282500840. Its totient is φ = 1371000096.

The previous prime is 4113000289. The next prime is 4113000341. The reversal of 4113000312 is 2130003114.

It is a junction number, because it is equal to n+sod(n) for n = 4113000291 and 4113000300.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85687483 + ... + 85687530.

Almost surely, 2^4113000312 is an apocalyptic number.

It is an amenable number.

4113000312 is an abundant number, since it is smaller than the sum of its proper divisors (6169500528).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4113000312 is a wasteful number, since it uses less digits than its factorization.

4113000312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171375022 (or 171375018 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 4113000312 is about 64132.6774117532. The cubic root of 4113000312 is about 1602.2105268671.

Adding to 4113000312 its reverse (2130003114), we get a palindrome (6243003426).

The spelling of 4113000312 in words is "four billion, one hundred thirteen million, three hundred twelve", and thus it is an aban number.