Base | Representation |
---|---|
bin | 1011111110000111111… |
… | …11001011011011000111 |
3 | 1110022122220100111212222 |
4 | 11333003333023123013 |
5 | 23214330330341403 |
6 | 512541521002555 |
7 | 41500434263144 |
oct | 5770377133307 |
9 | 1408586314788 |
10 | 411310012103 |
11 | 149487862941 |
12 | 6786aa8345b |
13 | 2ca2b85a9b3 |
14 | 15c9c2d13cb |
15 | aa747c3338 |
hex | 5fc3fcb6c7 |
411310012103 has 4 divisors (see below), whose sum is σ = 411702110400. Its totient is φ = 410917913808.
The previous prime is 411310012067. The next prime is 411310012111. The reversal of 411310012103 is 301210013114.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301210013114 = 2 ⋅150605006557.
It is a cyclic number.
It is not a de Polignac number, because 411310012103 - 26 = 411310012039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (411310012123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196047575 + ... + 196049672.
It is an arithmetic number, because the mean of its divisors is an integer number (102925527600).
Almost surely, 2411310012103 is an apocalyptic number.
411310012103 is a deficient number, since it is larger than the sum of its proper divisors (392098297).
411310012103 is a wasteful number, since it uses less digits than its factorization.
411310012103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 392098296.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 411310012103 its reverse (301210013114), we get a palindrome (712520025217).
The spelling of 411310012103 in words is "four hundred eleven billion, three hundred ten million, twelve thousand, one hundred three".
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