41131100321 has 2 divisors, whose sum is σ = 41131100322. Its totient is φ = 41131100320.

The previous prime is 41131100303. The next prime is 41131100323. The reversal of 41131100321 is 12300113114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41089317025 + 41783296 = 202705^2 + 6464^2 .

It is a cyclic number.

It is not a de Polignac number, because 41131100321 - 2¹⁴ = 41131083937 is a prime.

Together with 41131100323, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 41131100321.

It is not a weakly prime, because it can be changed into another prime (41131100323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20565550160 + 20565550161.

It is an arithmetic number, because the mean of its divisors is an integer number (20565550161).

Almost surely, 2^41131100321 is an apocalyptic number.

It is an amenable number.

41131100321 is a deficient number, since it is larger than the sum of its proper divisors (1).

41131100321 is an equidigital number, since it uses as much as digits as its factorization.

41131100321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 41131100321 its reverse (12300113114), we get a palindrome (53431213435).

The spelling of 41131100321 in words is "forty-one billion, one hundred thirty-one million, one hundred thousand, three hundred twenty-one".