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4113213212103 = 31780651239453
BaseRepresentation
bin111011110110101110100…
…111001100010111000111
3112120012220220022202122220
4323312232213030113013
51014342330040241403
612425330054023423
7603112154301642
oct73665647142707
915505826282586
104113213212103
111346449699576
12565202947b73
1323ab49c0ba78
1410311b18aa59
1571eda210953
hex3bdae9cc5c7

4113213212103 has 8 divisors (see below), whose sum is σ = 5806889240688. Its totient is φ = 2580839662464.

The previous prime is 4113213212093. The next prime is 4113213212117. The reversal of 4113213212103 is 3012123123114.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 4113213212103 - 25 = 4113213212071 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4113213212123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40325619676 + ... + 40325619777.

It is an arithmetic number, because the mean of its divisors is an integer number (725861155086).

Almost surely, 24113213212103 is an apocalyptic number.

4113213212103 is a deficient number, since it is larger than the sum of its proper divisors (1693676028585).

4113213212103 is a wasteful number, since it uses less digits than its factorization.

4113213212103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80651239473.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 4113213212103 its reverse (3012123123114), we get a palindrome (7125336335217).

The spelling of 4113213212103 in words is "four trillion, one hundred thirteen billion, two hundred thirteen million, two hundred twelve thousand, one hundred three".

Divisors: 1 3 17 51 80651239453 241953718359 1371071070701 4113213212103