Base | Representation |
---|---|
bin | 1011111110001010011… |
… | …00001100100110111000 |
3 | 1110022201022100021021102 |
4 | 11333011030030212320 |
5 | 23214401012431130 |
6 | 512543521430532 |
7 | 41501101013012 |
oct | 5770514144670 |
9 | 1408638307242 |
10 | 411330202040 |
11 | 1494981a293a |
12 | 6787579b448 |
13 | 2ca32aa96c4 |
14 | 15ca0c691b2 |
15 | aa76460645 |
hex | 5fc530c9b8 |
411330202040 has 16 divisors (see below), whose sum is σ = 925492954680. Its totient is φ = 164532080800.
The previous prime is 411330202037. The next prime is 411330202081. The reversal of 411330202040 is 40202033114.
It is a super-2 number, since 2×4113302020402 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5141627486 + ... + 5141627565.
Almost surely, 2411330202040 is an apocalyptic number.
411330202040 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
411330202040 is an abundant number, since it is smaller than the sum of its proper divisors (514162752640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
411330202040 is a wasteful number, since it uses less digits than its factorization.
411330202040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10283255062 (or 10283255058 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 411330202040 its reverse (40202033114), we get a palindrome (451532235154).
The spelling of 411330202040 in words is "four hundred eleven billion, three hundred thirty million, two hundred two thousand, forty".
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