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41135543040000 = 21135447317719
BaseRepresentation
bin10010101101001100111010…
…11011100011100000000000
312101122112000201111021211010
421112212131123203200000
520342431043004240000
6223253224012320520
711443642050450423
oct1126463533434000
9171575021437733
1041135543040000
111211a538710092
124744416173140
1319c50acc3ac46
14a22d842499ba
154b506ac68d50
hex25699d6e3800

41135543040000 has 960 divisors, whose sum is σ = 140593675622400. Its totient is φ = 10687332352000.

The previous prime is 41135543039989. The next prime is 41135543040019. The reversal of 41135543040000 is 4034553114.

It is a tau number, because it is divible by the number of its divisors (960).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a self number, because there is not a number n which added to its sum of digits gives 41135543040000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 57212159641 + ... + 57212160359.

It is an arithmetic number, because the mean of its divisors is an integer number (146451745440).

Almost surely, 241135543040000 is an apocalyptic number.

41135543040000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 41135543040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (70296837811200).

41135543040000 is an abundant number, since it is smaller than the sum of its proper divisors (99458132582400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

41135543040000 is an equidigital number, since it uses as much as digits as its factorization.

41135543040000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1128 (or 1093 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 30.

Adding to 41135543040000 its reverse (4034553114), we get a palindrome (41139577593114).

The spelling of 41135543040000 in words is "forty-one trillion, one hundred thirty-five billion, five hundred forty-three million, forty thousand".