Base | Representation |
---|---|
bin | 100110010100001100… |
… | …011101100101010011 |
3 | 10221012012001100222102 |
4 | 212110030131211103 |
5 | 1133224044004111 |
6 | 30522214231015 |
7 | 2654340506651 |
oct | 462414354523 |
9 | 127165040872 |
10 | 41141000531 |
11 | 164a2027694 |
12 | 7b8205546b |
13 | 3b5858a2c7 |
14 | 1dc3d3ddd1 |
15 | 110bc6b13b |
hex | 99431d953 |
41141000531 has 2 divisors, whose sum is σ = 41141000532. Its totient is φ = 41141000530.
The previous prime is 41141000449. The next prime is 41141000533. The reversal of 41141000531 is 13500014114.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41141000531 is a prime.
It is a super-2 number, since 2×411410005312 (a number of 22 digits) contains 22 as substring.
Together with 41141000533, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (41141000533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20570500265 + 20570500266.
It is an arithmetic number, because the mean of its divisors is an integer number (20570500266).
Almost surely, 241141000531 is an apocalyptic number.
41141000531 is a deficient number, since it is larger than the sum of its proper divisors (1).
41141000531 is an equidigital number, since it uses as much as digits as its factorization.
41141000531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 41141000531 its reverse (13500014114), we get a palindrome (54641014645).
The spelling of 41141000531 in words is "forty-one billion, one hundred forty-one million, five hundred thirty-one", and thus it is an aban number.
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