Base | Representation |
---|---|
bin | 111011110111100100101… |
… | …010010100001000000000 |
3 | 112120022021002121100210211 |
4 | 323313210222110020000 |
5 | 1014401204210000000 |
6 | 12430000045403504 |
7 | 603143505001303 |
oct | 73674452241000 |
9 | 15508232540724 |
10 | 4114120000000 |
11 | 134687453775a |
12 | 565416569594 |
13 | 23ac62a40c5a |
14 | 1031a5792b3a |
15 | 7203eb2d7ba |
hex | 3bde4a94200 |
4114120000000 has 320 divisors, whose sum is σ = 10354651617024. Its totient is φ = 1632960000000.
The previous prime is 4114119999953. The next prime is 4114120000027. The reversal of 4114120000000 is 214114.
It is a tau number, because it is divible by the number of its divisors (320).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6519999685 + ... + 6520000315.
Almost surely, 24114120000000 is an apocalyptic number.
4114120000000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 4114120000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5177325808512).
4114120000000 is an abundant number, since it is smaller than the sum of its proper divisors (6240531617024).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4114120000000 is an frugal number, since it uses more digits than its factorization.
4114120000000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 847 (or 801 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 13.
Adding to 4114120000000 its reverse (214114), we get a palindrome (4114120214114).
The spelling of 4114120000000 in words is "four trillion, one hundred fourteen billion, one hundred twenty million", and thus it is an aban number.
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