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4114120000000 = 2957163631
BaseRepresentation
bin111011110111100100101…
…010010100001000000000
3112120022021002121100210211
4323313210222110020000
51014401204210000000
612430000045403504
7603143505001303
oct73674452241000
915508232540724
104114120000000
11134687453775a
12565416569594
1323ac62a40c5a
141031a5792b3a
157203eb2d7ba
hex3bde4a94200

4114120000000 has 320 divisors, whose sum is σ = 10354651617024. Its totient is φ = 1632960000000.

The previous prime is 4114119999953. The next prime is 4114120000027. The reversal of 4114120000000 is 214114.

It is a tau number, because it is divible by the number of its divisors (320).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6519999685 + ... + 6520000315.

Almost surely, 24114120000000 is an apocalyptic number.

4114120000000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 4114120000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5177325808512).

4114120000000 is an abundant number, since it is smaller than the sum of its proper divisors (6240531617024).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4114120000000 is an frugal number, since it uses more digits than its factorization.

4114120000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 847 (or 801 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 13.

Adding to 4114120000000 its reverse (214114), we get a palindrome (4114120214114).

The spelling of 4114120000000 in words is "four trillion, one hundred fourteen billion, one hundred twenty million", and thus it is an aban number.