Base | Representation |
---|---|
bin | 1111010100111000… |
… | …1011100100000111 |
3 | 101121201110201122121 |
4 | 3311032023210013 |
5 | 31411204312203 |
6 | 1520124110411 |
7 | 203644400365 |
oct | 36516134407 |
9 | 11551421577 |
10 | 4114135303 |
11 | 182135a823 |
12 | 969995407 |
13 | 5074740b5 |
14 | 2b0584635 |
15 | 1912bd0bd |
hex | f538b907 |
4114135303 has 16 divisors (see below), whose sum is σ = 4620464640. Its totient is φ = 3640291200.
The previous prime is 4114135253. The next prime is 4114135307. The reversal of 4114135303 is 3035314114.
It is a cyclic number.
It is not a de Polignac number, because 4114135303 - 213 = 4114127111 is a prime.
It is a super-2 number, since 2×41141353032 = 33852218582781803618, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4114135307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6303 + ... + 90928.
It is an arithmetic number, because the mean of its divisors is an integer number (288779040).
Almost surely, 24114135303 is an apocalyptic number.
4114135303 is a deficient number, since it is larger than the sum of its proper divisors (506329337).
4114135303 is a wasteful number, since it uses less digits than its factorization.
4114135303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 97398.
The product of its (nonzero) digits is 2160, while the sum is 25.
The square root of 4114135303 is about 64141.5255743111. The cubic root of 4114135303 is about 1602.3578910897.
Adding to 4114135303 its reverse (3035314114), we get a palindrome (7149449417).
The spelling of 4114135303 in words is "four billion, one hundred fourteen million, one hundred thirty-five thousand, three hundred three".
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