Base | Representation |
---|---|
bin | 111011110111110000001… |
… | …010100101110011100001 |
3 | 112120022202112210022022012 |
4 | 323313300022211303201 |
5 | 1014402103112313101 |
6 | 12430031142322305 |
7 | 603151340364656 |
oct | 73676012456341 |
9 | 15508675708265 |
10 | 4114313010401 |
11 | 1346963486290 |
12 | 56546b129395 |
13 | 23ac93a1b9a9 |
14 | 1031c3275c2d |
15 | 72051a56bbb |
hex | 3bdf02a5ce1 |
4114313010401 has 8 divisors (see below), whose sum is σ = 4488536052000. Its totient is φ = 3740122399840.
The previous prime is 4114313010371. The next prime is 4114313010407. The reversal of 4114313010401 is 1040103134114.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4114313010401 - 218 = 4114312748257 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (4114313010407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7842116 + ... + 8350293.
It is an arithmetic number, because the mean of its divisors is an integer number (561067006500).
Almost surely, 24114313010401 is an apocalyptic number.
It is an amenable number.
4114313010401 is a deficient number, since it is larger than the sum of its proper divisors (374223041599).
4114313010401 is a wasteful number, since it uses less digits than its factorization.
4114313010401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16215519.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 4114313010401 its reverse (1040103134114), we get a palindrome (5154416144515).
The spelling of 4114313010401 in words is "four trillion, one hundred fourteen billion, three hundred thirteen million, ten thousand, four hundred one".
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