Base | Representation |
---|---|
bin | 101110110101111010111110… |
… | …1011100000111100100100111 |
3 | 2000000212210112220122122221200 |
4 | 1131223311331130013210213 |
5 | 413001204400221131330 |
6 | 4020152304323013543 |
7 | 152534162202453453 |
oct | 13553657534074447 |
9 | 2000783486578850 |
10 | 412031202130215 |
11 | 10a3164a6a75778 |
12 | 3a2664a7b0a2b3 |
13 | 148ba4b6391685 |
14 | 73a65b9197663 |
15 | 3297d25484a60 |
hex | 176bd7d707927 |
412031202130215 has 24 divisors (see below), whose sum is σ = 715729938480960. Its totient is φ = 219275352483264.
The previous prime is 412031202130157. The next prime is 412031202130217. The reversal of 412031202130215 is 512031202130214.
It is a happy number.
412031202130215 is a `hidden beast` number, since 4 + 1 + 2 + 0 + 312 + 0 + 2 + 130 + 215 = 666.
It is not a de Polignac number, because 412031202130215 - 212 = 412031202126119 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (412031202130217) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9887936980 + ... + 9887978649.
It is an arithmetic number, because the mean of its divisors is an integer number (29822080770040).
Almost surely, 2412031202130215 is an apocalyptic number.
412031202130215 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
412031202130215 is a deficient number, since it is larger than the sum of its proper divisors (303698736350745).
412031202130215 is a wasteful number, since it uses less digits than its factorization.
412031202130215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19775916103 (or 19775916100 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 412031202130215 its reverse (512031202130214), we get a palindrome (924062404260429).
Subtracting 412031202130215 from its reverse (512031202130214), we obtain a palindrome (99999999999999).
The spelling of 412031202130215 in words is "four hundred twelve trillion, thirty-one billion, two hundred two million, one hundred thirty thousand, two hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •