Base | Representation |
---|---|
bin | 101110110110011100111001… |
… | …0111010101010111101001101 |
3 | 2000001010202120010000120010111 |
4 | 1131230321302322222331031 |
5 | 413003403033222043000 |
6 | 4020245552112040021 |
7 | 152542351166436445 |
oct | 13554716272527515 |
9 | 2001122503016114 |
10 | 412104040034125 |
11 | 10a344384083a7a |
12 | 3a278635233011 |
13 | 148c43237479ba |
14 | 73a9d28a5d125 |
15 | 3299b89cbacba |
hex | 176ce72eaaf4d |
412104040034125 has 32 divisors (see below), whose sum is σ = 520911690624000. Its totient is φ = 325450246492800.
The previous prime is 412104040034111. The next prime is 412104040034131. The reversal of 412104040034125 is 521430040401214.
It is a happy number.
It is not a de Polignac number, because 412104040034125 - 219 = 412104039509837 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 49979544 + ... + 57638206.
It is an arithmetic number, because the mean of its divisors is an integer number (16278490332000).
Almost surely, 2412104040034125 is an apocalyptic number.
It is an amenable number.
412104040034125 is a deficient number, since it is larger than the sum of its proper divisors (108807650589875).
412104040034125 is an equidigital number, since it uses as much as digits as its factorization.
412104040034125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7664206 (or 7664196 counting only the distinct ones).
The product of its (nonzero) digits is 15360, while the sum is 31.
Adding to 412104040034125 its reverse (521430040401214), we get a palindrome (933534080435339).
The spelling of 412104040034125 in words is "four hundred twelve trillion, one hundred four billion, forty million, thirty-four thousand, one hundred twenty-five".
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