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4123011131 is a prime number
BaseRepresentation
bin1111010111000000…
…0010100000111011
3101122100011122222222
43311300002200323
531420442324011
61521042234255
7204113005421
oct36560024073
911570148888
104123011131
111826372318
1297095598b
13509261075
142b1815111
15191e72ddb
hexf5c0283b

4123011131 has 2 divisors, whose sum is σ = 4123011132. Its totient is φ = 4123011130.

The previous prime is 4123011031. The next prime is 4123011133. The reversal of 4123011131 is 1311103214.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4123011131 - 214 = 4122994747 is a prime.

It is a super-2 number, since 2×41230111312 = 33998441572699798322, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 4123011133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4123011133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2061505565 + 2061505566.

It is an arithmetic number, because the mean of its divisors is an integer number (2061505566).

Almost surely, 24123011131 is an apocalyptic number.

4123011131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4123011131 is an equidigital number, since it uses as much as digits as its factorization.

4123011131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 4123011131 is about 64210.6777023884. The cubic root of 4123011131 is about 1603.5093714165.

Adding to 4123011131 its reverse (1311103214), we get a palindrome (5434114345).

The spelling of 4123011131 in words is "four billion, one hundred twenty-three million, eleven thousand, one hundred thirty-one".