Base | Representation |
---|---|
bin | 100110011001100011… |
… | …110101010110000101 |
3 | 10221102110102111012221 |
4 | 212121203311112011 |
5 | 1133420114411003 |
6 | 30535151412341 |
7 | 2656512554503 |
oct | 463143652605 |
9 | 127373374187 |
10 | 41231013253 |
11 | 16538917571 |
12 | 7ba82240b1 |
13 | 3b71114c81 |
14 | 1dd1c91673 |
15 | 1114aeb7bd |
hex | 9998f5585 |
41231013253 has 2 divisors, whose sum is σ = 41231013254. Its totient is φ = 41231013252.
The previous prime is 41231013203. The next prime is 41231013269. The reversal of 41231013253 is 35231013214.
It is a happy number.
41231013253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 40289321284 + 941691969 = 200722^2 + 30687^2 .
It is a cyclic number.
It is not a de Polignac number, because 41231013253 - 29 = 41231012741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41231013203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20615506626 + 20615506627.
It is an arithmetic number, because the mean of its divisors is an integer number (20615506627).
Almost surely, 241231013253 is an apocalyptic number.
It is an amenable number.
41231013253 is a deficient number, since it is larger than the sum of its proper divisors (1).
41231013253 is an equidigital number, since it uses as much as digits as its factorization.
41231013253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 41231013253 its reverse (35231013214), we get a palindrome (76462026467).
The spelling of 41231013253 in words is "forty-one billion, two hundred thirty-one million, thirteen thousand, two hundred fifty-three".
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