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4124120043181 is a prime number
BaseRepresentation
bin111100000000111000101…
…101011100111010101101
3112121021002000110012011111
4330000320231130322231
51020032144212340211
612434332233152021
7603646352653165
oct74007055347255
915537060405144
104124120043181
111350036281156
1256734755b611
1323bb97744c78
141038739275a5
15724279e9421
hex3c038b5cead

4124120043181 has 2 divisors, whose sum is σ = 4124120043182. Its totient is φ = 4124120043180.

The previous prime is 4124120043151. The next prime is 4124120043187. The reversal of 4124120043181 is 1813400214214.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3925712158281 + 198407884900 = 1981341^2 + 445430^2 .

It is a cyclic number.

It is not a de Polignac number, because 4124120043181 - 25 = 4124120043149 is a prime.

It is a super-2 number, since 2×41241200431812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4124120043187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062060021590 + 2062060021591.

It is an arithmetic number, because the mean of its divisors is an integer number (2062060021591).

Almost surely, 24124120043181 is an apocalyptic number.

It is an amenable number.

4124120043181 is a deficient number, since it is larger than the sum of its proper divisors (1).

4124120043181 is an equidigital number, since it uses as much as digits as its factorization.

4124120043181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 31.

Adding to 4124120043181 its reverse (1813400214214), we get a palindrome (5937520257395).

The spelling of 4124120043181 in words is "four trillion, one hundred twenty-four billion, one hundred twenty million, forty-three thousand, one hundred eighty-one".