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4124132431 is a prime number
BaseRepresentation
bin1111010111010001…
…0100010001001111
3101122102021122010121
43311310110101033
531421234214211
61521122245411
7204125355466
oct36564242117
911572248117
104124132431
111826a68811
129711b6867
13509564563
142b1a279dd
151920e5271
hexf5d1444f

4124132431 has 2 divisors, whose sum is σ = 4124132432. Its totient is φ = 4124132430.

The previous prime is 4124132429. The next prime is 4124132473. The reversal of 4124132431 is 1342314214.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4124132431 - 21 = 4124132429 is a prime.

It is a super-2 number, since 2×41241324312 = 34016936616851939522, which contains 22 as substring.

Together with 4124132429, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 4124132396 and 4124132405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4124132401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062066215 + 2062066216.

It is an arithmetic number, because the mean of its divisors is an integer number (2062066216).

Almost surely, 24124132431 is an apocalyptic number.

4124132431 is a deficient number, since it is larger than the sum of its proper divisors (1).

4124132431 is an equidigital number, since it uses as much as digits as its factorization.

4124132431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2304, while the sum is 25.

The square root of 4124132431 is about 64219.4085226577. The cubic root of 4124132431 is about 1603.6547224741.

Adding to 4124132431 its reverse (1342314214), we get a palindrome (5466446645).

The spelling of 4124132431 in words is "four billion, one hundred twenty-four million, one hundred thirty-two thousand, four hundred thirty-one".