Base | Representation |
---|---|
bin | 101110111101001001110011… |
… | …1101000111100110001000101 |
3 | 2000011101211000211222010121110 |
4 | 1131322103213220330301011 |
5 | 413114000422024332401 |
6 | 4022233042112435233 |
7 | 152666036352303006 |
oct | 13572234750746105 |
9 | 2004354024863543 |
10 | 413025121324101 |
11 | 10a669a74498a70 |
12 | 3a3a7051548b19 |
13 | 1496014290b190 |
14 | 73dc745b991ad |
15 | 32b3ae7e509d6 |
hex | 177a4e7a3cc45 |
413025121324101 has 32 divisors (see below), whose sum is σ = 648125573018112. Its totient is φ = 230652590938560.
The previous prime is 413025121324063. The next prime is 413025121324103. The reversal of 413025121324101 is 101423121520314.
It is not a de Polignac number, because 413025121324101 - 29 = 413025121323589 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (413025121324103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 854787355 + ... + 855270408.
It is an arithmetic number, because the mean of its divisors is an integer number (20253924156816).
Almost surely, 2413025121324101 is an apocalyptic number.
It is an amenable number.
413025121324101 is a deficient number, since it is larger than the sum of its proper divisors (235100451694011).
413025121324101 is a wasteful number, since it uses less digits than its factorization.
413025121324101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1710058353.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 413025121324101 its reverse (101423121520314), we get a palindrome (514448242844415).
The spelling of 413025121324101 in words is "four hundred thirteen trillion, twenty-five billion, one hundred twenty-one million, three hundred twenty-four thousand, one hundred one".
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