413051001253 has 4 divisors (see below), whose sum is σ = 450601092288. Its totient is φ = 375500910220.

The previous prime is 413051001227. The next prime is 413051001281. The reversal of 413051001253 is 352100150314.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-413051001253 is a prime.

It is a super-2 number, since 2×413051001253² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (413051001203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18775045501 + ... + 18775045522.

It is an arithmetic number, because the mean of its divisors is an integer number (112650273072).

Almost surely, 2^413051001253 is an apocalyptic number.

It is an amenable number.

413051001253 is a deficient number, since it is larger than the sum of its proper divisors (37550091035).

413051001253 is a wasteful number, since it uses less digits than its factorization.

413051001253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37550091034.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 413051001253 its reverse (352100150314), we get a palindrome (765151151567).

The spelling of 413051001253 in words is "four hundred thirteen billion, fifty-one million, one thousand, two hundred fifty-three".