Base | Representation |
---|---|
bin | 111100000111110011001… |
… | …010010010010001001111 |
3 | 112121222020100022010121221 |
4 | 330013303022102101033 |
5 | 1020142400020144330 |
6 | 12442001003504211 |
7 | 604331330114233 |
oct | 74076312222117 |
9 | 15558210263557 |
10 | 4131543131215 |
11 | 13531a5430055 |
12 | 568879528067 |
13 | 23c7ab5b4356 |
14 | 103d797385c3 |
15 | 7270e537b7a |
hex | 3c1f329244f |
4131543131215 has 96 divisors (see below), whose sum is σ = 5611685235840. Its totient is φ = 2909232488448.
The previous prime is 4131543131203. The next prime is 4131543131237. The reversal of 4131543131215 is 5121313451314.
4131543131215 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4131543131215 - 215 = 4131543098447 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3339969577 + ... + 3339970813.
It is an arithmetic number, because the mean of its divisors is an integer number (58455054540).
Almost surely, 24131543131215 is an apocalyptic number.
4131543131215 is a deficient number, since it is larger than the sum of its proper divisors (1480142104625).
4131543131215 is a wasteful number, since it uses less digits than its factorization.
4131543131215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2609 (or 2590 counting only the distinct ones).
The product of its digits is 21600, while the sum is 34.
Adding to 4131543131215 its reverse (5121313451314), we get a palindrome (9252856582529).
The spelling of 4131543131215 in words is "four trillion, one hundred thirty-one billion, five hundred forty-three million, one hundred thirty-one thousand, two hundred fifteen".
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