413653151 has 2 divisors, whose sum is σ = 413653152. Its totient is φ = 413653150.

The previous prime is 413653103. The next prime is 413653153. The reversal of 413653151 is 151356314.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 413653151 - 2¹⁴ = 413636767 is a prime.

It is a super-2 number, since 2×413653151² = 342217858664457602, which contains 22 as substring.

Together with 413653153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (413653153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206826575 + 206826576.

It is an arithmetic number, because the mean of its divisors is an integer number (206826576).

Almost surely, 2^413653151 is an apocalyptic number.

413653151 is a deficient number, since it is larger than the sum of its proper divisors (1).

413653151 is an equidigital number, since it uses as much as digits as its factorization.

413653151 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5400, while the sum is 29.

The square root of 413653151 is about 20338.4648142381. The cubic root of 413653151 is about 745.0957947776.

The spelling of 413653151 in words is "four hundred thirteen million, six hundred fifty-three thousand, one hundred fifty-one".