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414001243301 is a prime number
BaseRepresentation
bin1100000011001000110…
…01011010010010100101
31110120121110101020001112
412001210121122102211
523240333304241201
6514104535234405
741624223335222
oct6014431322245
91416543336045
10414001243301
1114a6389aa758
12682a0218a05
133006a2940a9
14160758c0949
15ab80bc50bb
hex606465a4a5

414001243301 has 2 divisors, whose sum is σ = 414001243302. Its totient is φ = 414001243300.

The previous prime is 414001243297. The next prime is 414001243303. The reversal of 414001243301 is 103342100414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 362884555201 + 51116688100 = 602399^2 + 226090^2 .

It is a cyclic number.

It is not a de Polignac number, because 414001243301 - 22 = 414001243297 is a prime.

Together with 414001243303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (414001243303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207000621650 + 207000621651.

It is an arithmetic number, because the mean of its divisors is an integer number (207000621651).

Almost surely, 2414001243301 is an apocalyptic number.

It is an amenable number.

414001243301 is a deficient number, since it is larger than the sum of its proper divisors (1).

414001243301 is an equidigital number, since it uses as much as digits as its factorization.

414001243301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 414001243301 its reverse (103342100414), we get a palindrome (517343343715).

The spelling of 414001243301 in words is "four hundred fourteen billion, one million, two hundred forty-three thousand, three hundred one".