4142421131 has 2 divisors, whose sum is σ = 4142421132. Its totient is φ = 4142421130.

The previous prime is 4142421113. The next prime is 4142421133. The reversal of 4142421131 is 1311242414.

Together with previous prime (4142421113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4142421131 is a prime.

It is a super-2 number, since 2×4142421131² = 34319305653110638322, which contains 22 as substring.

Together with 4142421133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4142421097 and 4142421106.

It is not a weakly prime, because it can be changed into another prime (4142421133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2071210565 + 2071210566.

It is an arithmetic number, because the mean of its divisors is an integer number (2071210566).

Almost surely, 2^4142421131 is an apocalyptic number.

4142421131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4142421131 is an equidigital number, since it uses as much as digits as its factorization.

4142421131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 768, while the sum is 23.

The square root of 4142421131 is about 64361.6433211583. The cubic root of 4142421131 is about 1606.0217264241.

Adding to 4142421131 its reverse (1311242414), we get a palindrome (5453663545).

The spelling of 4142421131 in words is "four billion, one hundred forty-two million, four hundred twenty-one thousand, one hundred thirty-one".