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41431014433 = 1936040387
BaseRepresentation
bin100110100101011110…
…110001110000100001
310221221101202121021001
4212211132301300201
51134322314430213
631011054232001
72664461545354
oct464536616041
9127841677231
1041431014433
11166308003a6
1280431b5601
133ba369c973
14201067429b
1511274561dd
hex9a57b1c21

41431014433 has 8 divisors (see below), whose sum is σ = 43732409120. Its totient is φ = 39250428228.

The previous prime is 41431014421. The next prime is 41431014451. The reversal of 41431014433 is 33441013414.

It is a happy number.

It is not a de Polignac number, because 41431014433 - 221 = 41428917281 is a prime.

It is a super-2 number, since 2×414310144332 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41431014403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3013335 + ... + 3027052.

It is an arithmetic number, because the mean of its divisors is an integer number (5466551140).

Almost surely, 241431014433 is an apocalyptic number.

It is an amenable number.

41431014433 is a deficient number, since it is larger than the sum of its proper divisors (2301394687).

41431014433 is an frugal number, since it uses more digits than its factorization.

41431014433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6040444 (or 6040406 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 41431014433 its reverse (33441013414), we get a palindrome (74872027847).

The spelling of 41431014433 in words is "forty-one billion, four hundred thirty-one million, fourteen thousand, four hundred thirty-three".

Divisors: 1 19 361 6859 6040387 114767353 2180579707 41431014433