4143113120 has 24 divisors (see below), whose sum is σ = 9788105124. Its totient is φ = 1657245184.

The previous prime is 4143113111. The next prime is 4143113123. The reversal of 4143113120 is 213113414.

It can be written as a sum of positive squares in 2 ways, for example, as 4111887376 + 31225744 = 64124^2 + 5588^2 .

It is a super-2 number, since 2×4143113120² = 34330772650232268800, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 4143113092 and 4143113101.

It is not an unprimeable number, because it can be changed into a prime (4143113123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12947069 + ... + 12947388.

Almost surely, 2^4143113120 is an apocalyptic number.

4143113120 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

4143113120 is an abundant number, since it is smaller than the sum of its proper divisors (5644992004).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4143113120 is a wasteful number, since it uses less digits than its factorization.

4143113120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25894472 (or 25894464 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 4143113120 is about 64367.0188838974. The cubic root of 4143113120 is about 1606.1111497714. Note that the first 4 decimals are identical.

Adding to 4143113120 its reverse (213113414), we get a palindrome (4356226534).

The spelling of 4143113120 in words is "four billion, one hundred forty-three million, one hundred thirteen thousand, one hundred twenty".