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414431252101 is a prime number
BaseRepresentation
bin1100000011111100000…
…01110000111010000101
31110121201102111221020101
412001332001300322011
523242223400031401
6514215340004101
741640664343206
oct6017601607205
91417642457211
10414431252101
1114a839701729
12683a0230631
13301083b1679
14160b6a575ad
15aba8815101
hex607e070e85

414431252101 has 2 divisors, whose sum is σ = 414431252102. Its totient is φ = 414431252100.

The previous prime is 414431252083. The next prime is 414431252107. The reversal of 414431252101 is 101252134414.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 398899612225 + 15531639876 = 631585^2 + 124626^2 .

It is a cyclic number.

It is not a de Polignac number, because 414431252101 - 25 = 414431252069 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 414431252101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (414431252107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207215626050 + 207215626051.

It is an arithmetic number, because the mean of its divisors is an integer number (207215626051).

Almost surely, 2414431252101 is an apocalyptic number.

It is an amenable number.

414431252101 is a deficient number, since it is larger than the sum of its proper divisors (1).

414431252101 is an equidigital number, since it uses as much as digits as its factorization.

414431252101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 414431252101 its reverse (101252134414), we get a palindrome (515683386515).

The spelling of 414431252101 in words is "four hundred fourteen billion, four hundred thirty-one million, two hundred fifty-two thousand, one hundred one".