Base | Representation |
---|---|
bin | 111100100100011001000… |
… | …010011000100001001101 |
3 | 112201220110220012121002111 |
4 | 330210121002120201031 |
5 | 1021143233300134231 |
6 | 12504035212224021 |
7 | 606466161566644 |
oct | 74443102304115 |
9 | 15656426177074 |
10 | 4162243364941 |
11 | 1365219963042 |
12 | 572806a6b011 |
13 | 242661a6b01c |
14 | 10564cb7c35b |
15 | 7340987d4b1 |
hex | 3c91909884d |
4162243364941 has 2 divisors, whose sum is σ = 4162243364942. Its totient is φ = 4162243364940.
The previous prime is 4162243364893. The next prime is 4162243364977. The reversal of 4162243364941 is 1494633422614.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3141242246025 + 1021001118916 = 1772355^2 + 1010446^2 .
It is a cyclic number.
It is not a de Polignac number, because 4162243364941 - 225 = 4162209810509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4162243364141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2081121682470 + 2081121682471.
It is an arithmetic number, because the mean of its divisors is an integer number (2081121682471).
Almost surely, 24162243364941 is an apocalyptic number.
It is an amenable number.
4162243364941 is a deficient number, since it is larger than the sum of its proper divisors (1).
4162243364941 is an equidigital number, since it uses as much as digits as its factorization.
4162243364941 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2985984, while the sum is 49.
The spelling of 4162243364941 in words is "four trillion, one hundred sixty-two billion, two hundred forty-three million, three hundred sixty-four thousand, nine hundred forty-one".
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