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4162243364893 is a prime number
BaseRepresentation
bin111100100100011001000…
…010011000100000011101
3112201220110220012121000201
4330210121002120200131
51021143233300134033
612504035212223501
7606466161566545
oct74443102304035
915656426177021
104162243364893
111365219962aa9
12572806a6ab91
13242661a6acb3
1410564cb7c325
157340987d47d
hex3c91909881d

4162243364893 has 2 divisors, whose sum is σ = 4162243364894. Its totient is φ = 4162243364892.

The previous prime is 4162243364843. The next prime is 4162243364941. The reversal of 4162243364893 is 3984633422614.

It is a happy number.

4162243364893 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3547278430084 + 614964934809 = 1883422^2 + 784197^2 .

It is a cyclic number.

It is not a de Polignac number, because 4162243364893 - 29 = 4162243364381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4162243364843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2081121682446 + 2081121682447.

It is an arithmetic number, because the mean of its divisors is an integer number (2081121682447).

Almost surely, 24162243364893 is an apocalyptic number.

It is an amenable number.

4162243364893 is a deficient number, since it is larger than the sum of its proper divisors (1).

4162243364893 is an equidigital number, since it uses as much as digits as its factorization.

4162243364893 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17915904, while the sum is 55.

The spelling of 4162243364893 in words is "four trillion, one hundred sixty-two billion, two hundred forty-three million, three hundred sixty-four thousand, eight hundred ninety-three".