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4214012111 is a prime number
BaseRepresentation
bin1111101100101100…
…1011100011001111
3101212200101222212122
43323023023203033
532112241341421
61534052523155
7206266340411
oct37313134317
911780358778
104214012111
111872777741
129973204bb
135220737ba
142bd9429b1
15199e4b2ab
hexfb2cb8cf

4214012111 has 2 divisors, whose sum is σ = 4214012112. Its totient is φ = 4214012110.

The previous prime is 4214012107. The next prime is 4214012113. The reversal of 4214012111 is 1112104124.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4214012111 - 22 = 4214012107 is a prime.

Together with 4214012113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4214012111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4214012113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2107006055 + 2107006056.

It is an arithmetic number, because the mean of its divisors is an integer number (2107006056).

Almost surely, 24214012111 is an apocalyptic number.

4214012111 is a deficient number, since it is larger than the sum of its proper divisors (1).

4214012111 is an equidigital number, since it uses as much as digits as its factorization.

4214012111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 17.

The square root of 4214012111 is about 64915.4227514541. The cubic root of 4214012111 is about 1615.2209036875.

Adding to 4214012111 its reverse (1112104124), we get a palindrome (5326116235).

The spelling of 4214012111 in words is "four billion, two hundred fourteen million, twelve thousand, one hundred eleven".