Base | Representation |
---|---|
bin | 10011001111011100010000… |
… | …11000101111110000001101 |
3 | 12112210222200210112222210100 |
4 | 21213232020120233300031 |
5 | 21021214444310140300 |
6 | 225553511452201313 |
7 | 11624641035343143 |
oct | 1147561030576015 |
9 | 175728623488710 |
10 | 42312011021325 |
11 | 12533472171261 |
12 | 48b4426a69239 |
13 | 1a7c00c180936 |
14 | a63cab357593 |
15 | 4d5974aa4700 |
hex | 267b8862fc0d |
42312011021325 has 36 divisors (see below), whose sum is σ = 77070013319520. Its totient is φ = 22183924415520.
The previous prime is 42312011021299. The next prime is 42312011021327. The reversal of 42312011021325 is 52312011021324.
It is a happy number.
42312011021325 is a `hidden beast` number, since 4 + 2 + 31 + 201 + 102 + 1 + 325 = 666.
42312011021325 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 42312011021325 - 232 = 42307716054029 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (42312011021327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 1593659457 + ... + 1593686006.
It is an arithmetic number, because the mean of its divisors is an integer number (2140833703320).
Almost surely, 242312011021325 is an apocalyptic number.
42312011021325 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
It is an amenable number.
42312011021325 is a deficient number, since it is larger than the sum of its proper divisors (34758002298195).
42312011021325 is a wasteful number, since it uses less digits than its factorization.
42312011021325 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3187345538 (or 3187345530 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 42312011021325 its reverse (52312011021324), we get a palindrome (94624022042649).
Subtracting 42312011021325 from its reverse (52312011021324), we obtain a palindrome (9999999999999).
The spelling of 42312011021325 in words is "forty-two trillion, three hundred twelve billion, eleven million, twenty-one thousand, three hundred twenty-five".
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