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42551300311 = 133273176947
BaseRepresentation
bin100111101000010000…
…010101000011010111
311001211110210000120121
4213220100111003113
51144121113102221
631314154012411
73034314041062
oct475020250327
9131743700517
1042551300311
11170561107a3
1282b6417107
134021803c10
1420b93738d9
151190997a41
hex9e84150d7

42551300311 has 4 divisors (see below), whose sum is σ = 45824477272. Its totient is φ = 39278123352.

The previous prime is 42551300279. The next prime is 42551300347. The reversal of 42551300311 is 11300315524.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 42551300311 - 25 = 42551300279 is a prime.

It is a super-2 number, since 2×425513003112 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (42551300381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1636588461 + ... + 1636588486.

It is an arithmetic number, because the mean of its divisors is an integer number (11456119318).

Almost surely, 242551300311 is an apocalyptic number.

42551300311 is a deficient number, since it is larger than the sum of its proper divisors (3273176961).

42551300311 is a wasteful number, since it uses less digits than its factorization.

42551300311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3273176960.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 42551300311 its reverse (11300315524), we get a palindrome (53851615835).

The spelling of 42551300311 in words is "forty-two billion, five hundred fifty-one million, three hundred thousand, three hundred eleven".

Divisors: 1 13 3273176947 42551300311